PHYSICS EXPERIMENTS

discover everything from nature.....

slide 1

knowledge is power

develop scientific approach...

dream big

learning is continuous process....

inspire yourself and inspire others

develop concepts....

LEARNING BY DOING

combine experiments and theory....

GENERAL KNOWLEDGE - USEFUL for  ALL COMPETITIVE EXAMS...........

PHYSICS

5. What is the value of ' one KNOT' ?Ans: 1.852 Km/hr   and 'knot' is the unit of speed

CHEMISTRY:

1. What is the composition of a soap?
Ans: Potassium and Sodium salts with fatty acids.

Ans: non metal, conductor

3. Which metal remains in liquid form under normal conditions?
Ans: Mercury

4. What is the mass of electron?
Ans: 9.1 X 10 ^ -31 Kg.

5. Which fuel is used in rockets?
Ans: liquid oxygen

SPHERICAL MIRRORS ----  CURVED SURFACES  - KEY CONCEPTS

Let us look at the below diagram, reflection at plane surfaces i.e. at plane mirror. All the laws of reflection at plane surfaces are valid and applicable to spherical mirrors also.

SPHERICAL MIRROR ?

The mirrors which have curved surface are known as Spherical mirrors, these mirrors are part of a hollow glass sphere.

CONVEX MIRROR AND ITS TERMS

The spherical mirror is said to be convex if the bulged surface is made smooth and the inner surface is silvered.

CONCAVE MIRROR AND ITS TERMS

The spherical mirror is said to be concave if the bulged surface is silvered and the inner surface is made smooth.

SPHERICAL MIRRORS AND TERMS RELATED :

APERTURE: The surface of the mirror from which the reflection take place is called its aperture.

POLE: The central point on the surface of the mirror is called its pole (P)

CENTRE OF CURVATURE:

The centre of the sphere of which the spherical mirror is a part is called the centre of curvature of the mirror.

The radius of the sphere from which the spherical mirror is a part is called the radius of curvature of the mirror.

PRINCIPAL AXIS:

The line joining the pole and the centre of curvature is called the principal axis of the mirror.

FOCUS: (F)

The point on the principal axis where rays incident parallel to the principal axis converge to reappear or to diverge from after reflection is called the Focus of the spherical mirror.

FOCAL LENGTH (f):

The distance of the Focus from the pole is called the focal length (f) of the spherical mirror.

REAL AND VIRTUAL IMAGES:

An image formed by the actual intersection of light rays is called a real image. A real image is formed on the screen.

If the rays of light responsible for an image do not actually intersect, the image is called virtual image.

Virtual image cannot be formed on the screen, as no light reaches where the image appears to form.

Observe the following ray diagram when a parallel light incidents on a concave mirror and understand the reflection concepts........

IMAGES FORMED BY A CONVEX MIRROR:

Irrespective of the position of the object , The image formed by the convex mirror is always virtual and erect but when we compare the the size of the image, the image size  is always diminished.

PRINCIPAL FOCUS OF A CONVEX MIRROR
The principal focus of a convex mirror, which is divergent mirror,  is a point on the principal axis of the mirror, at which all the incident rays parallel to the principal axis appears to diverge after reflection from the mirror.

The principal focus of the convex mirror is virtual and always lies behind the convex mirror.

observe the above ray diagram when parallel rays incident on both concave mirror and convex mirror and observe the principal focus.

from the above ray diagrams, write down the characteristics of the image formed.

MIRROR FORMULA:

1/v + 1/u = 1/f

From the mirror formula, if we observe, we can understand that how the object distance,u, and image distance,v, are related to the focal length.  The distances are measured from the pole only. Pole to object is u, and pole to image is v,

MAGNIFICATION BY SPHERICAL MIRRORS:
Generally, we can understand that the magnification is the increase in the image size with respect to the size of the object which is produced by spherical mirrors.  The magnification is calculated by taking the ratio of height of the image to the height of the object ---- hi/ho.  It can also be calculated by the negative ratio of the image distance to the object distance.

What can we understand from the magnification ?

*** when 'm' value is positive it tells us image is virtual.
*** when 'm' value is negative it tells us image is real.

logical question combining mirror formula and magnification

FIND OUT THE OBJECT DISTANCE (u), when the magnification produced is 'm' and focal length is 'f'.

solution:

mirror formula is :  1/f = 1/v + 1/u

magnification is m = -v/u   so  v=-mu

substituting the 'm' value in formula:

1/f = 1/-mu   + 1/u

1/f = 1/u(1/-m + 1/u)

simplifying,   u = f/m(m-1)

critical thinking problems:

1. Suppose that you are given a concave mirror of focal length 15 cm.  Then,

a) To get the magnification m=1, where the object is needed to be placedb)  When the object is placed at 30 cm, write the characteristics of the image formed.c)  Your friend told that the image formed at infinity, where would be the object is placed.

2. When a student is performing experiment with concave mirror of focal length 20 cm, then he observed that the size of the image is reduced to 1/3rd of its size of the object.  Calculate the object distance in this situation.

Wednesday, 29 April 2020

COMPLETE STUDY MATERIAL ON CHEMICAL EQUATIONS - FOUNDATION TO ADVANCED

CHEMICAL REACTIONS - CHEMICAL EQUATIONS

INTRODUCTION:

In our daily life we all know about physical changes and chemical changes, all these changes are observed in our day today life.  We observe ice converts into water vapor and vice versa.  In this example, the changes in the states of matter are observed and heat may be gained or released.  Similarly, burning of wood also example.

CHEMICAL REACTION:

Chemical reactions represent the processes in which a single substance or substances undergo change to produce new substance or substances with different or new properties are called 'CHEMICAL REACTIONS'.

For example: When potassium nitrate gets heated potassium nitrite and oxygen are formed.  This is a chemical reaction since potassium nitrate changes into potassium nitrite and oxygen, these are new substances.

A chemical reaction consists of REACTANTS and PRODUCTS.

From the above example, potassium nitrate is called Reactant and potassium nitrite and oxygen are the products, since the substance which takes part in  chemical reaction is called Reactant and a new substance formed or substances formed in a chemical reaction, called products.

FIND OUT THE REACTANTS AND PRODUCTS from the following:

Calcium carbonate ----->  Calcium oxide and carbon dioxide

Sodium combines with water to get sodium hydroxide and hydrogen

HOW THE REACTANTS ARE TRANSFORMED INTO PRODUCTS ??????

Initially, the compounds or molecules break down into atoms and these atoms take part in the reaction then products are formed by new bonds formed between the atoms.

CHARACTERISTICS OF CHEMICAL REACTION:

How can we understand that there is a existence of chemical reaction and it took place, by observing the characteristics we can understand that there is a chemical reaction observed ......

1) When metals react with acids, we can observe there is evolution of Hydrogen gas.

2) Formation of precipitate when two solutions are mixed, the precipitate is a solid substance separated from the solution.  For example, lead iodide is a precipitate formed when lead acetate aq.solution combined with aq. sol. of potassium iodide.

3) Some times we observe the emission of heat such reactions are exothermic reactions, we know that when Calcium oxide is added to water, and sometimes the equipment becomes cold when ammonium chloride mixed with barium hydroxide.  These are called endothermic reactions.

CHEMICAL EQUATIONS  Vs CHEMICAL REACTIONS

We can understand with an example :

CaCO3 is the formula of Calcium carbonate and CaO is calcium oxide and CO2 is carbon dioxide.

The above is a chemical reaction, when it is represented with formula and symbols, that notation is known as chemical equation.

How can we write a chemical equation ??????

* the reactants and products in the reaction should be written with their formulae  or symbols.

* when more than one reactant or product, then + symbol is used

* an arrow mark is used in between reactants and products, the arrow mark also tells us in which way the reaction is taking place.

What information is conveyed by a chemical equation ???

* we understand the reactants and products in the reaction, and their number of atoms

* we can calculate the masses of the compounds or molecules in the reactants and products

* we come to know the number of moles of the reactants and products.

EXAMPLE:

When we observe the formation of water from hydrogen and oxygen :

There are :

four hydrogen atoms, two oxygen atoms gives two water molecules

two moles of hydrogen and one mole of oxygen to give two mole of water

four grams of hydrogen and thirty two grams of oxygen to give 36 g of water

we can also calculate number of atoms and volumes also.

2 H2 + O2 ------> 2 H2O

Generally,  a chemical equation do not represent any thing other than the reactants and products, but to make a chemical equation more informative, one has to represent :

* states of the reactants and products, s, l, g, aq.

* the evolution of gas with upward arrow line and precipitate with downward arrow line

* if heat is liberated, then in the products + heat should be written

* if heat is absorbed, then in the reactants + heat should be written.

TYPES OF CHEMICAL REACTIONS:

1) COMBINATION REACTIONS

2) DECOMPOSITION REACTIONS

3) SINGLE DISPLACEMENT REACTIONS OR SUBSTITUTION REACTIONS

4) DOUBLE DISPLACEMENT REACTIONS

WHAT IS THE DIFFERENCE BETWEEN BALANCED CHEMICAL EQUATION AND UNBALANCED CHEMICAL EQUATION ??

BALANCED CHEMICAL EQUATION : When the number of atoms of each element on both sides is  equal then the equation is said to be balanced chemical equation.

UNBALANCED CHEMICAL EQUATION: When the number of atoms of each element on both sides is not equal, then the equation is said to be unbalanced chemical equation.

HOW TO MAKE AN EQUATION A BALANCED EQUATION - STEPS TO BE REMEMBERED:

** must know the formulae of compounds or molecules of reactants or products and the subscriptions in the formulas should not be altered at any cost.

for example: always the calcium carbonate is CaCO3 and Hydrogen molecule  is H2 only.

TRIAL AND ERROR METHOD OF BALANCING A CHEMICAL EQUATION:

STEPS:

1) COUNT EACH TYPE OF ATOMS ON BOTH SIDES

2) IDENTIFY THE MOST COMPLICATED FORMULA AND COUNT THE NUMBER OF ATOMS OF EACH ELEMENT

3)  BY TRIAL AND ERROR METHOD, CHANGE THE NUMBER OF ATOMS ON BOTH SIDES TILL THE NUMBER OF ATOMS ON BOTH SIDES EQUAL.

EXAMPLES OF UNBALANCED AND BALANCED EQUATIONS:

1) KClO3 ---> KCl + O2

After balancing,

2KClO3 ----> 2 KCl + 3 O2

2) CaCO3 ---> CaO + CO2

3) AlCl3 + Ca(OH)2  ----> Al(OH)2 + CaCl2

2 AlCl3 + 3 Ca(OH)2  ----> 2 Al(OH)2 + 3 CaCl2

4) Al + H2SO4 ----> Al2(SO4)3   +  H2

After balancing:

2 Al + 3 H2SO4 ----> Al2(SO4)3   +  3 H2

How to balance a chemical equation? with algebraic expression method.

A chemical equation tells us the type of reaction between different reactants. Chemical equation gives the states of the reactants and products.  One can calculate the amount of products required for required amount of products.

To balance a chemical equation, very interesting method is algebraic expression method.

for example:  C3H8 + O2 -----> CO2  + H2O

The above reaction is to be balanced using algebraic expressions

step 1) the coefficients of Each reactants and products assumed to be a,b,c,d,...

aC3H8 + b O2 -----> c CO2  + d H2O

step 2) identify and count the number of elements on both sides of the reaction

carbon: 3a = c

hydrogen: 8a = 2d

oxygen:  2b = 2c + d

step 3) let us assume a=1, then simplify the equations for other variable values

c = 3,     2d = 8   then d = 4             if d=4 and c =3 then 2b=6 + 4 = 10, b=5

step 4) write the chemical equation using the variable values

C3H8 + 5O2 ---> 3CO2  + 4 H2O

step 5) count the number of atoms on both sides

carbon atoms  = 3
hydrogen atoms = 8
oxygen atoms = 10

step 6) we conclude that the equation is said to be balanced.

ASSIGNMENT ON BALANCING CHEMICAL EQUATIONS:

Friday, 24 April 2020

LABORATORY APPARATUS - USES

LABORATORY APPARATUS - HOW TO USE AND WHAT ARE THEIR ADVANTAGES ?

1, I am ‘Test tube’…..!

A test tube is a clear glass or plastic container that is much longer than its wide, commonly has a U-shaped bottom and has an open top.  Glass and special plastic test tubes are also non-reactive.  Many metals react with all sorts of chemicals in ways that would ruin an experiment or sample.
Chemists use test tubes to mix, heat and/or hold small quantities of chemicals for assays and laboratory experiment.  Biologists use them to culture and handle various organisms, fluids, and samples.

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2.  I am ‘Beaker’
A Beaker is a common container in most labs.  It is used for mixing, stirring, and heating chemicals.   It is generally a cylindrical container with a flat bottom.  Most also have a small spout to aid pouring.  Beaker is distinguished from a flask, by having straight rather than sloping slides.  Beakers are available in glass, and also in metal, plastics.

Any experiment which yields a liquid product uses a beaker to catch the liquid.

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SK’mCAn Erlenmeyer flask also known as a Conical Flask or a titration flask, which features a flat bottom, a conical body, and a cylindrical neck.  It is named after the German Chemist Emil Erlenmeyer (1825-1909), who created in 1860.
Erlenmeyer flasks have wide bases, with sides that taper upward to a short vertical neck.  They may be graduated, and often spots of ground glass or enamel are used.  It differs from the beaker in its tapered body and narrow neck.  Depending on the application, they may be constructed from glass or plastic in a wide range of volumes. The mouth of the Erlenmeyer flask may have a beaded lip that can be stopped or covered.

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4.  I am watch glass….

A watch glass is a circular concave piece of glass used in chemistry as a surface to evaporate a liquid., to hold solids while being weighted, for heating a small amount of substance and as a cover for a beaker.  It can be used to prevent dust or other particles entering the beaker, the watch glass does not completely seal the beaker, so gas exchanges still occur.  When used as an evaporation surface, a watch glass allows closer observation of precipitates or crystallization.

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5. PIPPETTE

Pipette or pipet is a laboratory tool commonly used in chemistry, biology, and medicine to transport a measured volume of liquid.

Pipette works by creating a partial vacuum above the liquid –holding chamber and selectively releasing this vacuum to draw up and dispense liquid.

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6. RUBBER STOPPERS

Rubber stoppers in the labs are used frequently to plug flasks and test tubes.  Its purpose is to prevent liquids, and gases, escaping from their containers and also to prevent contaminants from entering the containers.
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A GLASS FLASK USED IN LABORATORY FOR HOLDING CHEMICAL LIQUIDS AND SOLUTIONS, WHICH HAS A SPHERICAL SHAPE BODY FOR UNIFORM HEATING AND HAS CYLINDRICAL NECK. IT IS ALSO KNOWN  AS A BOILING FLASK, MOST OFTEN USED WHEN HEATING SOLUTIONS, PARTICULARLY FOR DISTILLATION

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8. FUNNEL

Glass funnels can be used to guard against spillage when pouring chemicals from one vessel to another, can be fitted with filter to separate solids from liquids.

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A graduated cylinder also called as measuring cylinder, used to measure the volume of liquids.  It is used accurately to measure the volume of chemicals for use in reactions.

REFLECTION AT CURVED SURFACES & REFRACTION AT CURVED SURFACES:

1. Magnification : m = -v/u  or m=hi/ho

2. Mirror formula, 1/f = 1/u + 1/v

3. focal length f = R/2

4. Lens formula 1/f = 1/v - 1/u

5. Lens makers fomula :  1/f = (n-1) (1/R1 - 1/R2)

6. The relation between refractive indices of media, object distance, image distance, and radius of curvature is given by :

n2/v - n1/u = (n2-n1)/R
7. In case of plane mirrors, R, F are infinity, then the power is equal to zero.

n2/v  = n1/u

8. The refractive index of prism is
n = sin{[A+D]/2}/SIN [A/2]

9. Speed of wave is , v = Frequency x wavelength

10. snell's law is n1sini = n2sinr

11. A + d = i1 + i2

PROBLEMS IN PHYSICS - REFLECTION AT CURVED SURFACES

PROBLEM 1:

Where is the image formed when 8 cm tall object is placed at 20 cm. in front of a concave mirror with focal length 5 cm.  Find out the size of the image also.

PROBLEM 2:

A 10 cm tall object is placed in front of a convex mirror of focal length 15 cm, Find out the image distance and write its characteristics .

b>PROBLEM 3:

10 cm focal length concave mirror is placed at 40 cm, from a wall.  Calculate the object distance such that its image is formed on the wall.

PROBLEM 4:

In front of 15 cm focal length concave mirror, an object is placed at 30 cm, if the object is displaced through 10 cm towards mirror, calculate by how much distance the image is displaced?

PROBLEM 5:

The image is formed behind the mirror, at a distance of 10 cm, when an object is placed at 20 cm in front of it.  Identify the type of mirror used and also calculate the focal length.

ELECTRICITY:

1. Electric current i = Q/t

2. Potential difference,  V =  W/Q

3. Resistance R = (Resistivity * length)/Area

4. Resistance R=V/I

5. Electric power P = V * I

6. P=V2/R

7. CONDUCTIVITY = 1/Resistivity

8. Resistors connected in series, R = R1 + R2 + R3 +.....

9. Resistors connected in parallel  1/R = 1/R1 + 1/R2 + 1/R3.......

MODEL PROBLEMS :

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1. If you are using an electric lamp and it lights for 6 hours and the current drawn by it is 0.24 A. Then calculate the amount of charge flowing through the lamp.

2. A circuit consists of five resistors, 10 ohm, 20 ohm, 30 ohm, 40 ohm, 50 ohm, your aim is to decrease the effective resistance using the given resistors, then how do you connect them and calculate the resultant resistance.

3. Suppose that you are using a water heater to heat the water having resistance of 90 ohm, and connected to 240 v. p.d. Determine the current flowing through the water heater.

4. Calculate the number of units when 50w, 60w, 80w electrical appliances are being used daily for 2 hours for 30 days.

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